LOCO SHED GOMOH

ACKNOWLEDGEMENT I would like to express my sincere grateful and profound gratitude to LOCO SHED ,GOMOH for providing an opportunity to undergo Vocational Training of 04 weeks in “ELECTRIC LOCO SHED, Gomoh, Jharkhand’’. I bear immense pleasure in expressing my gratitude and thanks to all the Employees of respective shops for their honest teaching, practical demonstration, guidance and suggestion in respective sections. Furthermore, I would like to acknowledge with much appreciation the crucial role of staffs, who gave us the permission to use all required equipment and the necessary materials during our training period. CONTENTS 1. Introduction 2. Locomotives 3. Syntaxs used in Loco 4. Components of Loco 5. Different Sections of Loco 6. Brake Rigging 7. Pantograph 8. Traction Converter 9. Working of Loco 10. Conclusion INTRODUCTION  The ISO-9001-2008 certified Electric Loco Shed, East Central Railway, Gomoh situated in Gomoh. ELECT...

Nodal analysis problem

* Using nodal method, determine the current in the individual of the circuit.
 Solution:-
Apply KCL in node 1:
 =  (100-V1/20) -  (V1- V2/15) -  (V1 - V 0/10)=0
 = -13 V1 + 4V2= -300
 = 13V1-4V2= 300
Apply KCL in node 2:
= (V1 - V2/15) - (V2 - 0/10)+( 80-V2/10)=0
= 2V1- 8V2 =- 240
 From equation (1) (2), we have,
         ∆= | 13           -4   |                  
               | 2            -8    |= -104 + 8= -96          D1= | 300       -4   |
        | -240      -8   | = -2400-960= -3360

D2= | 13            300   |
        |  2           -240    | = -3120 -600= -3720
So;
     V1= D1/∆= -3360/-96= 35V
     V2= D2/∆= -3720/-96= 38.75V
Form the above value of the nodal potential, we can now calculate the various branch current. Current through 20 Ohms resistor,  'I' 1 = (100-V1/20)= 100-35/20= 3.25A.
Current through 15 Ohms resistor,
'I'2 = (V1 - V2/15)= (35-38.75/15)= -0.25A.
Current through first 10 Ohms resistor,
'I'3 = (V1/10) = 35/10= 3.5A.
Current through second 10 Ohms resistor,
'I'4 = (V2/10)= 38.75/10 = 3.875A.
Current through third 10 Ohms resistor,
'I'5 = (80-V2/10)= 80-38.75/10= 4.125A.
Thank you.
Written by. Abhishek Singh E.E

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